When the positive integer "n" is divided by 3, the remainder is 2 and when "n" is divided by 5, the remainder is 1. What is the least possible value of "n" I really need this done out step by step and explained in detail. im not grasping it...

Answer:The number would be 11.Step-by-step explanation:Dividend = Divisor × Quotient + RemainderGiven,"n" is divided by 3, the remainder is 2,So, the number = 3n + 2,"n" is divided by 5, the remainder is 1,So, the number = 5n + 1Thus, we can write,3n + 2 = 5n + 1-2n = -1n = 0.5,Therefore, number must be the multiple of 0.5 but is not divided by 3 or 5,Possible numbers = { 1, 2, 4, 7, 8, 11...... }Since, 1 and 4 do not give the remainder 2 after divided by 3,And, 2, 7 and 8 do not give the remainder 1 after divided by 5,Hence, the least positive integer number that gives remainder 2 and 1 after divided by 3 and 5 respectively is 11.