Two containers, A and b begin with equal volumes of liquid. 120 mL is then poured from a to B. Container b now contains four times as much liquid as A. Find the volume of liquid left in container a at the end
Accepted Solution
A:
If n is used as the initial amount of liquid in both A and B:
4(n-120) = n+120 4n-480 = n+120 3n = 600 n = 200
Each container originally held 200ml. Container A now has 80ml and Container B has 320ml