MATH SOLVE

2 months ago

Q:
# Jean and Fred are making apple crisp. The recipe calls for 8 apples to be peeled and cut into pieces. However, as Fred and Jean work, they eat pieces of apple. Fred eats 2/9 of each apple that he peels, and Jean eats 1/9 of each apple she peels. Assuming they each peel and cut four apples, how many apples will they have left over for the recipe after they peel eight apples?

Accepted Solution

A:

Answer:[tex]\frac{20}{3} = 6\frac{2}{3}[/tex] i.e. six and two-third apples will be left.Step-by-step explanation:Fred eats [tex]\frac{2}{9}[/tex] of each apple that he peels and Jean eats [tex]\frac{1}{9}[/tex] of each apple that he peels.
So, if Fred peels 4 apples then he eats [tex]\frac{4 \times 2}{9} = \frac{8}{9}[/tex] of one apple.
And, if Jean peels 4 apples then he eats [tex]\frac{4 \times 1}{9} = \frac{4}{9}[/tex] of one apple.
Hence, total they peel (4 + 4) = 8 apples but they eat total [tex](\frac{8}{9} + \frac{4}{9}) = \frac{12}{9} = \frac{4}{3}[/tex] apples
Therefore, they will have left [tex]8 - \frac{4}{3} = \frac{24 - 4}{3} = \frac{20}{3} = 6\frac{2}{3} [/tex] {Since 20 = 6 Γ 3 + 2 } apples for the recipe after they peel eight apples. (Answer)